Converting Hexadecimal to Octal

I would suggest that the easiest way would be to convert hex --> binary --> octal

dec    hex(bin)     oct(bin)
 0      0(0000)      0(000)
 1      1(0001)      1(001)
 2      2(0010)      2(010)
 3      3(0011)      3(011)
 4      4(0100)      4(100)
 5      5(0101)      5(101)
 6      6(0110)      6(110)
 7      7(0111)      7(111)
 8      8(1000)
 9      9(1001)
 10     A(1010)
 11     B(1011)
 12     C(1100)
 13     D(1101)
 14     E(1110)
 15     F(1111)

so your number would be 59A17EDC

0101 1001 1010 0001 0111 1110 1101 1100

re space it in 3 digit groups from the right to left and add any needed leading zeroes

001 011 001 101 000 010 111 111 011 011 100

you should end up with the following

q13150277334

If you do not have to do it in one step the easiest is to convert to decimal first and then to octal

the easy way:

0xABCD = 1010 1011 1100 1101b => 1|010|101|111|001|101 = 125715(8)

to summarize in hex all this bits are in groups of 4... regrop into groups of 3

Found these articles on the topic:

1. How to convert hex to binary
2. How to convert binary to octal